Q: In \$C_{6}H_{14}\$, the number of possible structural isomers is:

\$C_6H_{14}\$ is hexane. It has 5 structural isomers viz. n-hexane, 2-methylpentane, 3-methylpentane, 2,2-dimethylbutane, 2,3-dimethylbutane.

Q: The number of isomers in \$C_{4}H_{10}O\$ are:

There are seven isomers in \$C_{4}H_{10}O\$. Out of these seven isomers, four are alcohol and three are ether.

Q: How many structure isomers can you draw for pentane?

Pentane (\$C_5H_{12}\$) is an organic compound and an alkane with five carbon atoms. Pentane has three structural isomers. These are n-pentane, Iso-pentane and neo-pentane. Pentane means exclusively the n-pentane isomer; the other two being called isopentane (methylbutane) and neopentane (dimethylpropane). Cyclopentane is not an isomer of pentane. Structures of all the three isomers are given here.Option B is correct.

Q: Among the isomeric alkanes of molecular formula \$C_5H_{12}\$, identify the one that on photochemical chlorination yields:(i) A single monochloride(ii) Three isomeric monochlorides(iii) Four isomeric monochlorides.

\$i)\$ To have a single mono-chloride , there should be only one type of \$H-atom\$. This is because, replacement of any \$H-atom\$ leads to the formation of same product.\$\therefore\$ The isomer \$C_5H_{12}\$ that leads to a single mono-chloride is neo-pentane.\$CH_{ 3 }-\overset { \underset { | }{ CH_{ 3 } } }{ \underset { \overset { | }{ CH_{ 3 } } }{ C } } -CH_{ 3 }\$\$ii)\$ To have \$3\$ isomeric mono-chlorides, the isomer should contain \$3\$ different types of \$H-atoms.\$\$\therefore\$ The isomer should be \$n-pentane.\$\$\overset { c }{ CH_{ 3 } } -\overset { b }{ CH_{ 2 } } -\overset { a }{ CH_{ 2 } } -\overset { b }{ CH_{ 2 } } -\overset { c }{ CH_{ 3 } } \$\$iii)\$ To have \$4\$ isomeric mono-chlorides, the isomer should contain \$4\$ different types of \$H-atoms.\$\$\therefore\$ The isomer is \$2-methylbutane.\$

Question 1

In $C_{6}H_{14}$, the number of possible structural isomers is:

Accepted Answer

$C_6H_{14}$ is hexane. It has 5 structural isomers viz. n-hexane, 2-methylpentane, 3-methylpentane, 2,2-dimethylbutane, 2,3-dimethylbutane.

Question 2

The number of isomers in $C_{4}H_{10}O$ are:

Accepted Answer

There are seven isomers in $C_{4}H_{10}O$. Out of these seven isomers, four are alcohol and three are ether.

Question 3

How many structure isomers can you draw for pentane?

Accepted Answer

Pentane ($C_5H_{12}$) is an organic compound and an alkane with five carbon atoms. Pentane has three structural isomers. These are n-pentane, Iso-pentane and neo-pentane. Pentane means exclusively the n-pentane isomer; the other two being called isopentane (methylbutane) and neopentane (dimethylpropane). Cyclopentane is not an isomer of pentane. Structures of all the three isomers are given here.Option B is correct.

Question 4

The total number of structural isomers possible for an amine with molecular formula $C_4H_{11}N$ is :

Accepted Answer

1. Primary Amines:n-butyl amine sec-butyl amine including 2 optical isomersiso-butyl aminetert-butyl amine2. Secondary aminesN-methyl n-propyl amineN-methyl isopropyl amineN, N-diethyl amine3. Tertiary amineN-ethyl N, N-dimethyl amine

Question 5

Which of the following compounds will exhibit geometrical isomerism?

Accepted Answer

1-phenyl-2-butene shows geometrical isomerism in the form of cis and trans isomers.However, the geometrical isomerism is not possible for 3-phenyl-1-butene, 2-phenyl-1-butene and 1,1-diphenyl-1-propane.

Question 6

Among the isomeric alkanes of molecular formula $C_{5} H_{12}$ , identify the one that on photochemical chlorination yields:
(i) A single monochloride
(ii) Three isomeric monochlorides
(iii) Four isomeric monochlorides.

Accepted Answer

$i)$ To have a single mono-chloride , there should be only one type of $H-atom$. This is because, replacement of any $H-atom$ leads to the formation of same product.$\therefore$ The isomer $C_5H_{12}$ that leads to a single mono-chloride is neo-pentane.$CH_{ 3 }-\overset { \underset { | }{ CH_{ 3 } }  }{ \underset { \overset { | }{ CH_{ 3 } }  }{ C }  } -CH_{ 3 }$$ii)$ To have $3$ isomeric mono-chlorides, the isomer should contain $3$ different types of $H-atoms.$$\therefore$ The isomer should be $n-pentane.$$\overset { c }{ CH_{ 3 } } -\overset { b }{ CH_{ 2 } } -\overset { a }{ CH_{ 2 } } -\overset { b }{ CH_{ 2 } } -\overset { c }{ CH_{ 3 } } $$iii)$ To have $4$ isomeric mono-chlorides, the isomer should contain $4$ different types of $H-atoms.$$\therefore$ The isomer is $2-methylbutane.$

Question 7

The number of stereoisomers possible for a compound of the molecular formula is:$CH_3-CH=CH-CH(OH)-Me$

Accepted Answer

d and l for cis form.d and l for trans form. So, total of 4 isomers are possible.

Question 8

The number of structural isomers possible from the molecular formula $C_3H_9N$ is :

Accepted Answer

The number of structural isomers possible from the molecular formula $C_3H_9N$ is $4$.

Question 9

Which of the following given compounds can exhibit tautomerism?

Accepted Answer

All the three compounds I, II and III can exhibit tautomerism.Option B is correct.

Question 10

Which of the following compounds will show metamerism?

Accepted Answer

Metamerism occurs when the compound has different number of carbon atoms on either side of the functional group.Only option B can show metamerism.$C_{2}H_{5}-S-C_{2}H_{5}$ is a metamer of $CH_{3}-S-C_{3}H_{7}$.

Revise with Concepts

Structural and Stereoisomerism

Quick Summary With Stories

Position Isomerism

Metamerism

Stereoisomerism

In $C_{6} H_{14}$ , the number of possible structural isomers is:

The number of isomers in $C_{4} H_{10} O$ are:

How many structure isomers can you draw for pentane?

The total number of structural isomers possible for an amine with molecular formula $C_{4} H_{11} N$ is :

Which of the following compounds will exhibit geometrical isomerism?

Among the isomeric alkanes of molecular formula $C_{5} H_{12}$ , identify the one that on photochemical chlorination yields:
(i) A single monochloride
(ii) Three isomeric monochlorides
(iii) Four isomeric monochlorides.

The number of stereoisomers possible for a compound of the molecular formula is: $C H_{3} - C H = C H - C H (O H) - M e$

The number of structural isomers possible from the molecular formula $C_{3} H_{9} N$ is :

Which of the following given compounds can exhibit tautomerism?

Which of the following compounds will show metamerism?

Revise with Concepts

Structural and Stereoisomerism

Quick Summary With Stories

Position Isomerism

Metamerism

Stereoisomerism

In C6​H14​, the number of possible structural isomers is:

The number of isomers in C4​H10​O are:

How many structure isomers can you draw for pentane?

The total number of structural isomers possible for an amine with molecular formula C4​H11​N is :

Which of the following compounds will exhibit geometrical isomerism?

Among the isomeric alkanes of molecular formula C5​H12​, identify the one that on photochemical chlorination yields: (i) A single monochloride (ii) Three isomeric monochlorides (iii) Four isomeric monochlorides.

The number of stereoisomers possible for a compound of the molecular formula is:CH3​−CH=CH−CH(OH)−Me

The number of structural isomers possible from the molecular formula C3​H9​N is :

Which of the following given compounds can exhibit tautomerism?

Which of the following compounds will show metamerism?

In $C_{6} H_{14}$ , the number of possible structural isomers is:

The number of isomers in $C_{4} H_{10} O$ are:

The total number of structural isomers possible for an amine with molecular formula $C_{4} H_{11} N$ is :

Among the isomeric alkanes of molecular formula $C_{5} H_{12}$ , identify the one that on photochemical chlorination yields:
(i) A single monochloride
(ii) Three isomeric monochlorides
(iii) Four isomeric monochlorides.

The number of stereoisomers possible for a compound of the molecular formula is: $C H_{3} - C H = C H - C H (O H) - M e$

The number of structural isomers possible from the molecular formula $C_{3} H_{9} N$ is :