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Class 11
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Gravitation
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Newton's Law of Gravitation
Newton's Law of Gravitation
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Universal Law of Gravitation - L1
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Definitions
Formulaes
The Gravitational Constant
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Universal Law of Gravitation
4 mins
Universal law of Gravitation and Vectorial Representation
11 mins
Newton's Law of Gravitation from Kepler's Law of Periods
4 mins
Universal Law of Gravitation
9 mins
Problems on Universal Law of Gravitation
7 mins
Experimental Estimation of value of G
6 mins
Force of Gravitation and Principle of Superposition
7 mins
Quick Summary With Stories
Newton's Law of Gravitation from Kepler's Law of Periods
3 mins read
Force of Gravitation and Principle of Superposition
2 mins read
Universal Law of Gravitation & Vectorial Representation
2 mins read
Universal Law of Gravitation - L1
3 mins read
Experimental Estimation of Value of "G".
2 mins read
Important Questions
Calculate the force of gravitation between the earth and the Sun, given that the mass of the earth
$=6×10_{24}$
kg and of the Sun
$=2×10_{30}kg$
. The average distance between the two is
$1.5×10_{11}$
m.
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Two particles of equal mass m go around a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is
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Two spherical bodies of mass M and 5M and radii R and 2R respectively are released in free space with initial separation between their centres equal to 12R. If they attract each other due to gravitational force only. then the distance covered by the smaller body just before collision is
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If the distance between centres of the earth and the moon is
$d$
and the mass of the earth is
$81$
times the mass of the moon, then at what distance from centre of the earth, the gravitational field will be zero?
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What is the magnitude of the gravitational force between the earth and a
$1kg$
object on its surface? (Mass of the earth is
$6×10_{24}kg$
and radius of the earth is
$6.4×10_{6}m$
.)
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Two spheres of masses m and M are situated in air and the gravitational force between them is F. The space around the masses is now filled with a liquid of specific gravity
$3$
. The new gravitational force will be :
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Dimensional formula of universal gravitational constant
$G$
is-
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>
A geostationary satellite is orbiting the earth at a height of
$5R$
above the surface of the earth has a time period of
$24$
hours.
$R$
being the radius of the earth.The time period of another satellite in hours at a height
$2R$
from the surface of the earth is
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A mass
$M$
is split into two parts
$m$
and
$(M−m)$
, which are, then separated by a certain distance. The ratio
$m/M$
which maximizes the gravitational force between the parts is
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Kepler's third law states that square of period of revolution
$(T)$
of a planet around the sun, is proportional to third power of average distance
$r$
between sun and planet
i.e
$T_{2}=Kr_{3}$
here
$K$
is constant.
If the masses of sun and planet are
$M$
and
$m$
respectively than as per Newton's law of gravitation force of attraction between them is
$F=r_{2}GMm $
, here
$G$
is gravitational constant The relation between
$G$
and
$K$
is described as
Hard
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>