Solve
Study
Textbooks
Guides
Use app
Login
>>
Class 11
>>
Physics
>>
Work, Energy and Power
>>
Work Done by a Variable Force
Work Done by a Variable Force
Revise with Concepts
Work Done by a Variable Force
Example
Definitions
Formulaes
>
Work Done by a Variable Force - Problem L1
Example
Definitions
Formulaes
>
Learn with Videos
Work done by a Variable Force
16 mins
Problems on Work Done by Variable Force
9 mins
Quick Summary With Stories
Work done by a Variable Force
2 mins
Work Done by a Variable Force - Problem L1
3 mins
Work Done by a Variable Force - Problem L2
3 mins
Work Done by a Variable Force - Graphical - Problem L1
2 mins
View more
Important Questions
The upper half of an inclined plane of inclination
$θ$
is perfectly smooth while the lower half rough. A block starting from rest at the top of the plane will again come to rest at the bottom if the coefficient of friction between the block and the lower half of the plane is given by.
Hard
View solution
>
A position dependent force
$F=7−2x+3x_{2}$
newton (where x is in meter) on a small body of mass 2 Kg & displace it from
$x=0$
to
$x=5$
m. Calculate the work done.
Medium
View solution
>
Derive the formula for kinetic energy.
Medium
View solution
>
Consider a drop of rain water having mass
$1g$
falling from a height of
$1km$
. It hits the ground with a speed of
$50m/s$
. Take '
$g$
' constant with a value
$10m/s_{2}$
. The work done by the (i) gravitational force the (ii) resistive force of airs is:
Hard
NEET
View solution
>
An object of Mass
$40kg$
is raised to a height of
$5m$
above the ground what is its potential energy? If the object is allowed to fall, find its kinetic energy when it is half way down.
Medium
View solution
>
A bullet fired into a fixed target loses half of its velocity after penetrating
$3cm$
. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion ?
Medium
View solution
>
$300J$
of work is done in sliding a
$2kg$
block up an inclined plane of height
$10m$
. The work done against friction is (Take
$g=10m/s$
$_{2}$
)
Medium
View solution
>
A body of mass 3 kg is under a constant force which causes a displacement s in metres in it,given by the relation
$s=21 t_{2}$
, where t is in seconds. Work done by the force in 2 seconds is:-
Medium
View solution
>
A particle moves along the x- axis from x=0 to x=5 m under the influence of a force given by
$F=7−2x+3x_{2}$
.Work done in the process is
Medium
View solution
>
A force acts on a
$3$
g particle in such a way that the position of the particle as a function of time is given by
$x=3t−4t_{2}+t_{3}$
, where
$x$
is in meters and
$t$
is in seconds. The work done during the first
$4$
second is :
Medium
View solution
>