Solve
Study
Textbooks
Guides
Use app
Login
>>
Class 12
>>
Physics
>>
Dual Nature of Radiation and Matter
>>
Wave Nature of Matter
Wave Nature of Matter
Revise with Concepts
Wave Nature of Matter
Example
Definitions
Formulaes
>
Wave Nature of Matter - Problem L1
Example
Definitions
Formulaes
>
Learn with Videos
de Broglie Wavelength
6 mins
Heisenberg Uncertainity Principle
7 mins
Quantum Mechanics.
6 mins
Quick Summary With Stories
De Broglie Wavelength
2 mins
Heisenberg Uncertainty Principle
2 mins
Wave Nature of Matter - Problem L1
2 mins
Wave Nature of Matter - Problem L1
2 mins
View more
Important Questions
A proton and an alpha particle both are accelerated through the same potential difference. The ratio of corresponding de-Broglie wavelengths is :
Medium
View solution
>
An electron (of mass m) and a photon have the same energy E in the range of a few eV. The ratio of the de-Broglie wavelength associated with the electron and the wavelength of the photon is (c = speed of light in vacuum)
Hard
View solution
>
An electromagnetic wave of wavelength
$λ$
is incident on a photosensitive surface of negligible work function. If the photoelectrons emitted from this surface have the de Brogue wavelength
$λ_{′}$
, then
Hard
View solution
>
An electron is accelerated from rest through a potential difference of
$V$
volt. If the de Broglie wavelength of the electron is
$1.227×10_{−2}nm$
, the potential difference is :
Medium
View solution
>
An electron, an alpha particle and a proton have the same kinetic energy. Which one of these particles has (i) the shortest and (ii) the largest, de Broglie wavelength?
Medium
View solution
>
An
$α$
- particle and a proton are accelerated from rest by the same potential. Find the ratio of their de- Broglie wavelength.
Medium
View solution
>
If the kinetic energy of the particle is increased to 16 times its previous value, the percentage change in the de-Broglie wavelength of the particle is :
Medium
View solution
>
Light of wavelength
$500nm$
is incident on a metal with a work function
$2.28eV$
. The de Borglie wavelength of the emitted electron is:
Hard
View solution
>
Derive an expression for de Broglie wavelength of matter waves.
Medium
View solution
>
What is the de Broglie wavelength of the electron accelerated through a potential difference of 100 Volt?
Medium
View solution
>