Solve
Study
Textbooks
Guides
Use app
Login
>>
Class 12
>>
Physics
>>
Electrostatic Potential and Capacitance
>>
Effects of Dielectrics in Capacitors
Effects of Dielectrics in Capacitors
Revise with Concepts
Basic Knowledge of Effect of Dielectric on Capacitance of Parallel Plate Capacitor
Example
Definitions
Formulaes
>
Electric Displacement
Example
Definitions
Formulaes
>
Learn with Videos
Capacitance of the parrallel plate capacitor with dielectric slab
13 mins
Parallel plate capacitor with dielectric in series and parallel
11 mins
Parallel plate capacitor with dielectric of different thickness
12 mins
Quick Summary With Stories
Capacitance of the Parallel Plate Capacitor with Dielectric Slab
2 mins
Relation between dielectric constant and suspectibility, Dielectric strength
2 mins
Electric Displacement
3 mins
Important Questions
A parallel plate capacitor is charged by a battery, which is then disconnected. A dielectric slab is then inserted in the space between the plates. Explain what changes, if any, occur in the values of
(i) capacitance.
(ii) potential difference between the plates.
(iii) electric field between the plates.
(iv) the energy stored in the capacitor.
Hard
View solution
>
A parallel plate capacitor of area
A,
plate separation
d
and capacitance
C
is filled with three different dielectric materials having dielectric constants
K
1
,
K
2
,
K
3
as shown. If a single dielectric material is to be used to have the same capacitance
C
in this capacitor then its dielectric constant
K
is given by
Medium
View solution
>
A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF =
1
0
−
1
2
F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
Medium
View solution
>
The capacitance of a parallel plate capacitor with air as medium is
6
μ
F
. With the introduction of a dielectric medium, the capacitance becomes
3
0
μ
F
. The permittivity of the medium is :
(
∈
0
=
8
.
8
5
×
1
0
−
1
2
C
2
N
−
1
m
−
2
)
Medium
View solution
>
A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor but has thickness
3
d
/
4
, where d is the distance between plates. How is the capacitors changed when the slab is inserted between the plates?
Medium
View solution
>
A parallel plate capacitor is made of two dielectric blocks in series. One of the blocks has thickness
d
1
and dielectric constant
K
1
and the other has thickness
d
2
and dielectric constant
K
2
as shown in figure. This arrangement can be thought as a dielectric slab of thickness d (=
d
1
+
d
2
) and effective dielectric constant K. The K is
Hard
View solution
>
A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates:
Medium
View solution
>
A slab of material of dielectric constant K has the same area as that of the plates of a parallel plate capacitor but has the thickness d/2, where d is the separation between the plates. Find out the expression for its capacitance when the slab is inserted between the plates of the capacitor .
Hard
View solution
>
A parallel plate capacitor with air between the plates has capacitance of
9
p
F
. The separation between its plates is '
d
'. The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant
k
1
=
3
and thickness
3
d
while the other one has dielectric constant
k
2
=
6
and thickness
3
2
d
. Capacitance of the capacitor is now :
Hard
View solution
>
A parallel plate capacitor has plates of area 'A' separated by distance 'd' between them. It is filled with a dielectric which has a dielectric constant that varies as
k
(
x
)
=
K
(
1
+
α
x
)
where 'x' is the distance measured from one of the plates. If
(
α
d
)
<
<
1
, the total capacitance of the system is best by the expression:
Hard
JEE Mains
View solution
>