**Example:**A mass of $2kg$ tied to a string of $1m$ length is rotating in a vertical circle with a uniform speed of $4ms_{−1}$.Find the position of mass when tension in the string will be $52N$.[Take $g=10ms_{−2}$]

**Solution:**

$T−mgsinθ=Rmv_{2} $ ($θ$ is the angle from the horizontal line

Thus we get: $52−2×10×sinθ=12×16 $

Thus $sinθ=90_{o}$

Thus the tension of 52 N would occur at the bottom most point.