What happens when white phosphorus is heated with concentrated \$NaOH\$ solution in an inert atmosphere of \$CO_{2}\$?

White phosphorous dissolves in boiling NaOH solution (in a \$CO_2\$ atmosphere) to give phosphine (\$PH_3\$). The reaction is as follows: \$P_4\$ + \$3NaOH\$ + \$3H_2O\$ \$\rightarrow\$ \$\underset{phosphine}{PH_3}\$ + \$3NaH_2PO_2\$

The product formed in the reaction of \${SOCl}_{2}\$ with white phosphorus is ?

The reaction involved is \$P_4+8SOCl_2\longrightarrow 4PCl_3+4SO_2+2S_2Cl_2\$Phosphorous trichloride is the product formed when \$SOCl_2\$ reacts with white phosphorous.

Why nitrogen exists as diatomic molecule \$(N_2)\$ and Phosphorus as \$P_4\$?

Nitrogen exists as diatomic molecule (N\$\displaystyle _2\$) with triple bond between two N atoms and phosphorus as P\$\displaystyle _4\$. Nitrogen can form \$\displaystyle p\pi-p\pi\$ multiple bonds. Phosphorous cannot form such bonds due to repulsion between non bonded electrons of inner core. In case of nitrogen, there is no such repulsion as it has only 1s electrons in inner shell so that the overlap of p orbitals to form pi bonds is easy.

White phosphorus reacts with caustic soda. The products are \$PH_3\$ and \$NaH_2PO_2\$. This reaction is an example of________.

Reactions, in which a compound undergoes both oxidation and reduction simultaneously, are called disproportionation.White phosphorus reacts with caustic soda. The products are phosphine \$PH_3\$ and sodium hypophosphite \$NaH_2PO_2\$. This reaction is an example of disproportionation.\$ P_4 +3NaOH+ 3H_2O \longrightarrow 3NaH_2PO_2 + PH_3\$Option (D) is correct.

Sulphuryl chloride \$(SO_2Cl_2)\$ reacts with white phosphorus \$(P_4)\$ to give:

Sulphuryl chloride (\$SO_2Cl_2\$) reacts with white phosphorus (\$P_4\$) to give phosphorous pentachloride and sulphur dioxide.\$\displaystyle 10SO_2Cl_2 + P_4 \rightarrow 4PCl_5 + 10SO_2\$Hence, option A is correct.

The reaction of white phosphorus with aqueous \$NaOH\$ gives phosphine along with another phosphorus containing compound. The reaction type, the oxidation states of phosphorus in phosphine and the other product are respectively:

Hint: Disproportionation reaction is a reaction in which the same element gets oxidized and gets reduced from one initial oxidation state.Step 1: Write down the reaction:\$P_{4(white)} + NaOH \rightarrow PH_3 + NaH_2PO_2\$Step 2: Calculate the oxidation state of phosphorous in the various phosphorous compounds:Let the oxidation number of \$P\$ be \$x\$ in each case\$P_4 \rightarrow 4x=0 \implies x=0\$\$PH_3 \rightarrow x+3 = 0 \implies x=-3\$\$NaH_2PO_2 \rightarrow +1+2+x-4 =0 \implies x= +1\$Final Answer: Hence the correct option is C.

Complete the following reaction, \$P_4+NaOH + H_2O\rightarrow \ \ \ \ ?\$

The balanced reaction between \$P_4\$ and \$NaOH\$ along with \$H_2O\$ gives phosphine and sodium hypophosphite.\${P_4}+3NaOH+3H_2O\overset{\Delta}{\rightarrow}\ {PH_3}+ {3NaH_2PO_2}\$.Hence, option B is correct.

Which of the following are correct statements about white phosphorus \$(P_4)\$ ?

A) Out of five valence electrons of P atom, 3 electrons are involved in bond formation with three other P atoms and one lone pair is remaining.Thus, statement A is correct.B) White phosphorus has a pyramidal structure with a bond angle of \$60^0\$.Thus, statement B is incorrect.C) A \$P_4\$ molecule has six P-P bonds.Thus, statement C is correct.D) White phosphorus disproportionates on reaction with alkalis.\$P_4+3NaOH+3H_2O \rightarrow \underset {sodium\ hypophosphite } {3NaH_2PO_2} + \underset {phosphine} {PH_3}\$Thus, the statement D is correct.

White phosphorus on reaction with concentrated \$NaOH\$ solution in an inert atmosphere of \${CO}_{2}\$ gives phosphine and compound \$(X)\$. \$(X)\$ on acidification with \$HCl\$ gives compound \$(Y)\$. The basicity of compound \$(Y)\$ is :

The basicity of compound \$Y\$ is 1. Hence, option \$C\$ is correct.

The reaction of \${P}_{4}\$ with \$X\$ leads selectively to \${P}_{4}{O}_{6}\$. The \$X\$ is:

Phosphorus trioxide (\$P_4O_6\$) is prepared by heating phosphorus in the limited supply of oxygen and nitrogen. \${ P }_{ 4 }+3{ { O }_{ 2 } }\xrightarrow [ ]{ { O }_{ 2 }+{ N }_{ 2 } } { P }_{ 4 }{ O }_{ 6 }\$\${N}_{2}\$ prevents further oxidation of \${ P }_{ 4 }{ O }_{ 6 }\$ to \${ P }_{ 4 }{ O }_{ 10 }\$.

Phosphorus and its Allotropes | Definition, Examples, Diagrams

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Allotropes of phosphorous

The allotropes of phosphorous are red, black and white phosphorous.

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White phosphorous

White or yellow phosphorus (

P_{4}

) is prepared from bone ash.

2 C a_{3} (P O_{4})_{2} (b o n e - a s h) + 10 C + 6 S i O_{2} h e a t 6 C a S i O_{3} + 10 C O + P_{4} (s)

(electric furnace method)

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Properties of white phosphorous

Properties:
It is white-to-transparent and soft waxy solid.
It is soluble in

C S_{2}

but insoluble in water.
It glows in dark due to slow oxidation producing yellowish-green light.

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Red phosphorous

When white phosphorus is heated in the atmosphere of

C O_{2}

or coal gas at

30 0^{0} C

, red phosphorous is produced.
It has more atoms linked together in a network than white phosphorus does, which makes it much more stable. It is not quite as flammable, but given enough energy it still reacts with air. For this reason, we now use red phosphorus in matches.

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Properties of red phosphorous

Properties:

It is a reddiish-voilet crystalline solid.

It is stable in air

It is less reactive than white phosphorous and does not dissolve in liquid $C S_{2}$ .

It is polymeric substance and form chain like structure.

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Black phosphorous

The most stable form of phosphorous is black phosphorous. It has two forms:

α

-phosphorous and

β

-phosphorous.

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Properties of black phosphorous

It has two forms:

α

black phosphorous and

β

black phosphorous. It can be sublimed in the air and has opaque monoclinic or rhombohedral crystals. It is very stable allotrope of phosphorous. It does not conduct electricity. It is highly polymerised form of phosphorous and has black metallic lustre.

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Reactivity of allotropes of phosphorus

White phosphorus is the most reactive while black phosphorus is the least reactive. Therefore, white phosphorus is stored under water to protect it from air while red and black are stable in air.

Phosphorus and its Allotropes

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Allotropes of phosphorous

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White phosphorous

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Properties of white phosphorous

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Red phosphorous

definition

Properties of red phosphorous

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Black phosphorous

definition

Properties of black phosphorous

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Reactivity of allotropes of phosphorus

Quick Summary With Stories

Phosphorous and its Allotropes

What happens when white phosphorus is heated with concentrated $N a O H$ solution in an inert atmosphere of $C O_{2}$ ?

The product formed in the reaction of $S O C l_{2}$ with white phosphorus is ?

Why nitrogen exists as diatomic molecule $(N_{2})$ and Phosphorus as $P_{4}$ ?

White phosphorus reacts with caustic soda. The products are $P H_{3}$ and $N a H_{2} P O_{2}$ . This reaction is an example of________.

Sulphuryl chloride $(S O_{2} C l_{2})$ reacts with white phosphorus $(P_{4})$ to give:

The reaction of white phosphorus with aqueous $N a O H$ gives phosphine along with another phosphorus containing compound. The reaction type, the oxidation states of phosphorus in phosphine and the other product are respectively:

Complete the following reaction, $P_{4} + N a O H + H_{2} O \to ?$

Which of the following are correct statements about white phosphorus $(P_{4})$ ?

White phosphorus on reaction with concentrated $N a O H$ solution in an inert atmosphere of $C O_{2}$ gives phosphine and compound $(X)$ . $(X)$ on acidification with $H C l$ gives compound $(Y)$ . The basicity of compound $(Y)$ is :

The reaction of $P_{4}$ with $X$ leads selectively to $P_{4} O_{6}$ . The $X$ is:

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Allotropes of phosphorous

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White phosphorous

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Properties of white phosphorous

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Red phosphorous

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Properties of red phosphorous

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Black phosphorous

definition

Properties of black phosphorous

definition

Reactivity of allotropes of phosphorus

Quick Summary With Stories

Phosphorous and its Allotropes

What happens when white phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO2​?

The product formed in the reaction of SOCl2​ with white phosphorus is ?

Why nitrogen exists as diatomic molecule (N2​) and Phosphorus as P4​?

White phosphorus reacts with caustic soda. The products are PH3​ and NaH2​PO2​. This reaction is an example of________.

Sulphuryl chloride (SO2​Cl2​) reacts with white phosphorus (P4​) to give:

The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type, the oxidation states of phosphorus in phosphine and the other product are respectively:

Complete the following reaction, P4​+NaOH+H2​O→ ?

Which of the following are correct statements about white phosphorus (P4​) ?

White phosphorus on reaction with concentrated NaOH solution in an inert atmosphere of CO2​ gives phosphine and compound (X). (X) on acidification with HCl gives compound (Y). The basicity of compound (Y) is :

The reaction of P4​ with X leads selectively to P4​O6​. The X is:

What happens when white phosphorus is heated with concentrated $N a O H$ solution in an inert atmosphere of $C O_{2}$ ?

The product formed in the reaction of $S O C l_{2}$ with white phosphorus is ?

Why nitrogen exists as diatomic molecule $(N_{2})$ and Phosphorus as $P_{4}$ ?

White phosphorus reacts with caustic soda. The products are $P H_{3}$ and $N a H_{2} P O_{2}$ . This reaction is an example of________.

Sulphuryl chloride $(S O_{2} C l_{2})$ reacts with white phosphorus $(P_{4})$ to give:

The reaction of white phosphorus with aqueous $N a O H$ gives phosphine along with another phosphorus containing compound. The reaction type, the oxidation states of phosphorus in phosphine and the other product are respectively:

Complete the following reaction, $P_{4} + N a O H + H_{2} O \to ?$

Which of the following are correct statements about white phosphorus $(P_{4})$ ?

White phosphorus on reaction with concentrated $N a O H$ solution in an inert atmosphere of $C O_{2}$ gives phosphine and compound $(X)$ . $(X)$ on acidification with $H C l$ gives compound $(Y)$ . The basicity of compound $(Y)$ is :

The reaction of $P_{4}$ with $X$ leads selectively to $P_{4} O_{6}$ . The $X$ is: