In terms of Charles' law, explain why - 273 \$\displaystyle ^{\circ}C\$ is the lowest possible temperature.

At \$0 \ K\$ or \$\displaystyle -273^oC \$, the volume of the gas becomes equal to zero . The gas ceases to exists. Hence, \$\displaystyle -273^oC\$ is the lowest possible temperature.

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Temperature as Measure of Hotness and Coldness and It's Units

Q: A circular metal loop is heated at point \$O\$ as shown in above Figure.i) In which direction would heat flow in the loop?ii) In which order the pins at points P, Q and R fixed with the help of wax fall if points O, P, Q and R are equidistant from each other?

According to the given condition.i) The heat will flow in the direction from O to P and O to R.ii) Firstly the pins at R and P will fail concurrently followed by the pin at Q.

Q: \$1\$ mole of \$H_2SO_4\$ is mixed with \$2\$ moles of NaOH. The heat evolved will be:

\${H}_{2}S{O}_{4} + 2 NaOH \longrightarrow {Na}_{2}S{O}_{4} + 2 {H}_{2}O\$According to reaction,\$1\$ mole \${H}_{2}S{O}_{4}\$ completely neutralised by \$2\$ mole of \$NaOH\$.As we know,Gram equivalent \$=\$ no. of moles \$\times\$ Valency factorValency factor of \${H}_{2}S{O}_{4} = 2\$Therefore,Gram equivalent of \${H}_{2}S{O}_{4} = 1 \times 2 = 2\$As we know,Heat evolved in the neutralisation of \$1\$ gm eq. of strong acid \$= 57.3 \; kJ\$Heat evolved in neutralisation of \$2\$ gm eq. of strong acid \$= \left( 57.3 \times 2 \right) kJ\$Hence the heat evolved will be \$2 \times 57.3 \; kJ\$.Hence, the correct option is \$\text{B}\$

Q: The value of absolute zero temperature in Fahrenheit scale is

Absolute temperature in Celsius is \$-273.15{{\,}^{o}}C\$ \$ F=\dfrac{9}{5}C+32 \$ \$ F=\dfrac{9}{5}\times (-273.15)+32=-459.67{{\,}^{o}}F \$ \$ F\cong -460{{\,}^{o}}F \$ Hence, absolute temperature in Fahrenheit

Q: Figure shows two flasks connected to each other. The volume of the flask 1 is twice that of flask 2. The system is filled with an ideal gas at temperature 100 K and 200 K respectively in the flasks. If the mass of the gas in 1 m, then what is the mass of the gas in flask 2 in equilibrium?

At equilibrium pressure in both the flasks must be same.Using ideal gas equation;\$\dfrac { { n }_{ 1 }R{ T }_{ 1 } }{ { V }_{ 1 } } =\dfrac { { n }_{ 2 }{ RT }_{ 2 } }{ { V }_{ 2 } } \$\$\dfrac { { m }_{ 1 }\times100K }{ { 2V }_{ 2 } } =\dfrac { { m }_{ 2 }\times200K }{ { V }_{ 2 } } \$\${ m }_{ 2 }=\dfrac { m }{ 4 } \$So, the correct option is \$C\$

Q: When two bodies at different temperatures are placed in thermal contact with each other, heat flows from the body at a higher temperature until they both acquire the same temperature. Assuming that there is no loss of heat to the surroundings, then:

Heat is a form of energy that gets transferred from one medium or object to another medium/object. Suppose if we a colder body and a hotter body and if it brought in contact, the heat gets transferred from the hotter body to colder body until the system of hotter & colder attains equilibrium.When two bodies at different temperatures are placed in thermal contact with each other, heat flows from the body at a higher temperature until they both acquire the same temperature. Assuming that there is no loss of heat to the surroundings, then The heat lost by the hotter body will be equal to the heat gained by the colder body.option D is correct

Q: Alka was making tea in a kettle. Suddenly she felt intense heat from the puff of steam gushing out of the spout of the kettle. She wondered whether the temperature of the steam was higher than that of the water boiling in the kettle. Comment.

The boiling point of water is 100°C. The temperature of boiling water does not rise instead of continuous supply of heat, as the extra heat is supplied to the water is used to turn water into steam. Hence, steam has a lot of latent heat which can cause severe burn. That’s why Alka felt intense heat from the puff of steam gushing out of the spout of the kettle.

Q: Absolute zero can be defined as the temperature at which:

A gas ceases to exist at absolute zero. It is the lowest temperature which can be attained, where volume becomes zero.

Q: For the reaction : \$2A(g)+3B\longrightarrow 4C(G) _D (l); \Delta H-=-20 kJ/mole\$Find the heat evolved when \$0.4\$ mole of A reacts with an excess of B in a closed rigid container. The temperature is constant at \$300 K\$. [R=8.3 J/K mole]

\$2 {A}_{\left( g \right)} + 3 {B}_{\left( g \right)} \longrightarrow 4 {C}_{\left( g \right)} + {D}_{\left( l \right)}\$No. of moles of A \$= 0.4\$No. of moles of C when \$2\$ moles of A reacts \$= 4 \text{ moles}\$No. of moles of C when \$0.4\$ moles of A reacts \$= 0.8 \text{ moles}\$No. of moles of B \$= 3\$ (As B is in excess)Total moles of reactant \$= 0.4 + 3 = 3.4\$Total moles of product \$= 0.8\$\${\Delta{n}}_{g} = {n}_{P} - {n}_{R} = 0.8 - 3.8 = -3\$\$\Delta{H} = -20 \; {KJ}/{mol}= -20000\; {J}/{mol}\$Temperature \$\left( T \right) = 300 K\$\$\Delta{H} = {q}_{V} + {\Delta{n}}_{g}RT\$\$\Rightarrow {q}_{V} = \Delta{H} - {\Delta{n}}_{g} RT\$\$\Rightarrow {q}_{V} = -20000 - \left( -3 \times 8.3 \times 300 \right) = -20000 + 7470 = -12530 \; {J}/{mol} = -12.53 \; {KJ}/{mol}\$Hence the required answer is \$-12.53 \; {KJ}/{mol}\$.

Physics

definition

Temperature

Temperature is a quantity which tells the thermal state of a body (i.e. the degree of hotness or coldness of the body).
Its units are: Kelvin(

K

), degree celsius(

^{o} C

) and degree fahrenheit(

^{o} F

definition

Temperature measuring instruments

Some instruments to measure temperature are thermometer, thermocouple, thermistor etc.

definition

Classification of Hot and Cold Objects

An object is considered hot if its temperature rises from normal temperature. For example : fire,vessel on fire,burning coal, etc.
An object is considered cold if its temperature reduces or its very low.For example : Ice cubes and dry ice.

REVISE WITH CONCEPTS

Heat and Temperature

ExampleDefinitionsFormulaes

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Hot and Cold

4 mins

Quick Summary With Stories

Temperature As Measure Of Hotness Or Coldness

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Introduction to Heat and Temperarture

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Important Questions

In terms of Charles' law, explain why - 273 $^{\circ} C$ is the lowest possible temperature.

Medium

View solution

A circular metal loop is heated at point $O$ as shown in above Figure.
i) In which direction would heat flow in the loop?
ii) In which order the pins at points P, Q and R fixed with the help of wax fall if points O, P, Q and R are equidistant from each other?

Medium

View solution

$1$ mole of $H_{2} S O_{4}$ is mixed with $2$ moles of NaOH. The heat evolved will be:

Medium

View solution

The value of absolute zero temperature in Fahrenheit scale is

Medium

View solution

Figure shows two flasks connected to each other. The volume of the flask 1 is twice that of flask 2. The system is filled with an ideal gas at temperature 100 K and 200 K respectively in the flasks. If the mass of the gas in 1 m, then what is the mass of the gas in flask 2 in equilibrium?

Medium

View solution

When two bodies at different temperatures are placed in thermal contact with each other, heat flows from the body at a higher temperature until they both acquire the same temperature. Assuming that there is no loss of heat to the surroundings, then:

Medium

View solution

Alka was making tea in a kettle. Suddenly she felt intense heat from the puff of steam gushing out of the spout of the kettle. She wondered whether the temperature of the steam was higher than that of the water boiling in the kettle. Comment.

Easy

View solution

Absolute zero can be defined as the temperature at which:

Medium

View solution

For the reaction : $2 A (g) + 3 B ⟶ 4 C (G)_{D} (l); Δ H - = - 20 k J / m o l e$
Find the heat evolved when $0.4$ mole of A reacts with an excess of B in a closed rigid container. The temperature is constant at $300 K$ . [R=8.3 J/K mole]

Medium

View solution

The measure of degree of hotness or coldness of a body is called:

Medium

View solution

definition

Temperature

definition

Temperature measuring instruments

definition

Classification of Hot and Cold Objects

REVISE WITH CONCEPTS

Heat and Temperature

Quick Summary With Stories

Temperature As Measure Of Hotness Or Coldness

Introduction to Heat and Temperarture

In terms of Charles' law, explain why - 273 ∘C is the lowest possible temperature.

A circular metal loop is heated at point O as shown in above Figure. i) In which direction would heat flow in the loop? ii) In which order the pins at points P, Q and R fixed with the help of wax fall if points O, P, Q and R are equidistant from each other?

1 mole of H2​SO4​ is mixed with 2 moles of NaOH. The heat evolved will be:

The value of absolute zero temperature in Fahrenheit scale is

Figure shows two flasks connected to each other. The volume of the flask 1 is twice that of flask 2. The system is filled with an ideal gas at temperature 100 K and 200 K respectively in the flasks. If the mass of the gas in 1 m, then what is the mass of the gas in flask 2 in equilibrium?

When two bodies at different temperatures are placed in thermal contact with each other, heat flows from the body at a higher temperature until they both acquire the same temperature. Assuming that there is no loss of heat to the surroundings, then:

Alka was making tea in a kettle. Suddenly she felt intense heat from the puff of steam gushing out of the spout of the kettle. She wondered whether the temperature of the steam was higher than that of the water boiling in the kettle. Comment.

Absolute zero can be defined as the temperature at which:

For the reaction : 2A(g)+3B⟶4C(G)D​(l);ΔH−=−20kJ/mole Find the heat evolved when 0.4 mole of A reacts with an excess of B in a closed rigid container. The temperature is constant at 300K. [R=8.3 J/K mole]

The measure of degree of hotness or coldness of a body is called:

In terms of Charles' law, explain why - 273 $^{\circ} C$ is the lowest possible temperature.

A circular metal loop is heated at point $O$ as shown in above Figure.
i) In which direction would heat flow in the loop?
ii) In which order the pins at points P, Q and R fixed with the help of wax fall if points O, P, Q and R are equidistant from each other?

$1$ mole of $H_{2} S O_{4}$ is mixed with $2$ moles of NaOH. The heat evolved will be:

For the reaction : $2 A (g) + 3 B ⟶ 4 C (G)_{D} (l); Δ H - = - 20 k J / m o l e$
Find the heat evolved when $0.4$ mole of A reacts with an excess of B in a closed rigid container. The temperature is constant at $300 K$ . [R=8.3 J/K mole]