Example: A bicycle chain of length 1.6 m and of mass 1 kg is lying on a horizontal floor. What is the work done in lifting it with one end touching the floor and the other end 1.6 m above the floor? (Takeg=10ms−2)
Solution: Consider chain to be concentrated on its center of mass. Therefore, change in potential energy = work done by external force. Work done=mg2h=8 J