Question 1

Chloroform gives salicylaldehyde on treatment with phenol in the presence of a base. This reaction is called as:

Accepted Answer

Reimer-Tiemann reaction: In this reaction chloroform gives salicylaldehyde on treatment with phenol in the presence of a base.The correct option is 'B'.

Question 2

Conversion of glucose to ethyl alcohol can be carried by:

Accepted Answer

Zymase is an enzyme complex that catalyzes the fermentation of sugar into ethanol and carbon dioxide.It is used to convert glucose to ethyl alcohol.Hence, option C is correct.

Question 3

The product forms when an alkyl halide reacts with an alkoxide is:

Accepted Answer

When an alkyl halide reacts with an alkoxide, the product forms is an ether. This reaction is known as Williamson's ether synthesis.An example of this synthesis is:  CH_3CH_2ONa+CH_3CH_2Cl\rightarrow C_2H_5OC_2H_5+NaCl     alkoxide                alkyl halide               etherOption C is correct.

Question 4

The compound formed when aniline reacts with benzene diazonium chloride is:

Accepted Answer

Aniline reacts with benzene diazonium chloride to form p-amino azobenzene.

Question 5

In the reaction series:  { C }_{ 6 }{ H }_{ 5 }Cl\xrightarrow [Cu _{ 2 }O,\: 200^oC ]{NH_3} X; X\xrightarrow [ { 0-5 }^{ 0 }C ]{ { HNO }_{ 2 } } Z; X+Z\rightarrow A , the number of  \sigma   and  \pi   bonds in  A  are:

Accepted Answer

Nucleophilic substitution of chloro-benzene with ammonia gives aniline. { C }_{ 6 }{ H }_{ 5 }Cl\xrightarrow [ { Cu }_{ 2 }O,\: { 200 }^{ 0 }C ]{ { NH }_{ 3 } } \underset {X} {C_6H_5NH_2} +HCl  Diazotization of aniline gives benzene diazonium chloride.  \underset {X} {C_6H_5NH_2} \xrightarrow [ { 0-5 }^{ 0 }C ]{ { HNO }_{ 2 } } \underset {Z} {C_6H_5N_2Cl} Azo coupling of aniline with benzenediazonium chloride gives p-aminoazobenzene.  \underset {X} {C_6H_5NH_2}+ \underset {Z} {C_6H_5N_2Cl}\rightarrow \underset {A} {C_6H_5-N=N-C_6H_4-NH_2} The number of   \sigma   and  \pi   bonds in  C_6H_5-N=N-C_6H_4-NH_2  are  27 \sigma   and  7 \pi  .Hence, the correct option is C.

Question 6

The correct IUPAC name of the compound is:

Accepted Answer

The correct IUPAC name of the compound is 3-methyl butane-1,2-diol. A methyl substituent is present on third C atom and  -OH   substituents are present on first and second C atoms.Note:  The longest chain of C atoms containing the  -OH  group is &#10;selected as the parent alkane and numbered from the end closer to &#10; -OH  group.

Question 7

A compound  A  has molecular formula  C_{7} H_{7} NO . On treatment with  Br_{2}  and  KOH ,  A  gives an amine  B  which gives carbylamine test.  B  upon diazotization and coupling with phenol gives an azo dye.  A  can be:

Accepted Answer

According to the reactions given for compound  B ,  B  should be aniline as it gives carbylamine test and also couples with phenol to form dye. The action of  Br_2  and  KOH   is Hoffmann bromamide reaction in which aniline is formed. Therefore,  A  should be an amide.Thus,  A  is  C_6H_5CONH_2 .Option B is correct.

Question 8

Which of the following catalyst is used in the conversion of water gas and hydrogen into methyl alcohol?

Accepted Answer

Water gas is an equimolar mixture of  CO  and  H_2 .A mixture of  zinc oxide and chromium oxide  (ZnO-Cr_{2}O_{3})  converts water gas into methanol  (CH_3OH) .The temperature of the reaction is 573 K.  CO + H_2 \xrightarrow {ZnO-Cr_{2}O_{3}} CH_3OH Option D is correct.

Question 9

Question 10

Hydrogen chloride and  SO_{2}  are the side products in the reaction of ethanol with thionyl chloride. Which of the following is main product in this reaction?

Accepted Answer

Chlorination of ethanol is done by using thionyl chloride. The complete reaction is: C_2H_5OH + SOCl_2 \rightarrow C_2H_5Cl + HCl + SO_2 Here, the major product formed is ethyl chloride.So, the correct option is 'D'.

Alcohols, Phenols And Ethers