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**Tip 1:**

**Voltage division in a series circuit:**

- First of all, find the equivalent (total) resistance of the circuit by simply adding up all the series resistors.
- Now the current drawn can be obtained by using the net resistance and the supply voltage.
- Now as the current remains constant for all the resistors, the voltage across any resistance can be obtained using Ohm's law.

Considering a shortcut, the voltage across any particular resistance can be obtained by using the formula:

$V_{R}=V_{s}R_{total}R $

Where $V_{R}$ is the voltage drop across particular resistance, $R$ is the resistance, and $V_{s}$ is the voltage of the source.

A power supply of electromotive force (e.m.f) $50V$ and negligible internal resistance connected in series with resistors of resistance $100Ω$ and $5Ω$ as shown

A voltmeter measures the potential difference (p.d) across the $5Ω$ resistor and an ammeter measures the current in the circuit.

What are suitable ranges for the ammeter and for the voltmeter?