Problem solving tips
3 min read

Thermal Properties Of Matter

- Want to score better marks in exams? Have a look at some problem solving tips.
1
Tips: Calculate actual measurement with scale at different temperature
In the scenario when the length of scale and object changing with temperature and we have to find correct measurement using the given scale. Use following strategy :
Let Scale gives correct measurement temperature and we have given scale measurement at (say ).
Step 1: Find length of scale at temperature (Assume ).
Step 2: Find change in length of scale .
So, Actual measurement of object at temperature would be
Now we know the actual length of given object at temperature .
Using above measurement of object we will find the length of object at all given temperature
2
Tips 2: Tips to Calculation of ratio of ice and water present at equilibrium temperature
If in a question you have given that some amount of ice is added to limited amount of water at certain temperature. From the question, if you are not sure what will be the final state of a mixture (water or ice) then follow the following steps
  • Assume, the heat released is positive heat, Heat absorbed is negative heat.
  • Calculate heat involved to bring all ice and water at ice. (After doing this Container have only ice at )
    • If value of heat is coming positive: Ice will melt according to amount of positive heat.
    • If all ice melt into water and still heat is in excess amount then temperature of water will increase.
    • If heat is not sufficient to melt all ice then we will see water and ice in the container.
  • If value of heat is showing negative: it mean that at equilibrium ice will exist and its temperature will be below
3
Tips 3: Tips to calculate temperature at the junction of multiple conductor
In the questions, if you have given the end temperature of every conductor and you have to find temperature at the junction then follow following tip.
  • Assume temperature of junction is .
  • In given steady condition, Assume heat is moving from junction to outer end of every conductor. So sum of heat current at the junction would be zero.
ie;
Where R: Represent thermal resistance of respective conductors.