Relation between dielectric constant and suspectibility, Dielectric strength

The capacitance of the parallel plate capacitor determines the amount of charge that it can hold.

The distance between the two plates is $d$ and the area of the medium between the plates is $A$.

According to Gauss’s law, the capacitance of the capacitor is.

Let’s first study the relationship between dielectric constant and electric susceptibility.

The dielectric property plays a major role in the functioning of the capacitor.

Suppose there is a parallel plate capacitor with dielectric medium which has electric field $E_{p}$ due to the polarization.

Now $E_{0}$ is the electric field present between the parallel plate capacitor.

Hence the net electric field $E$ of the parallel plate capacitor with dielectric medium is.

The value of the $E_{p}$ in which $σ_{p}$ is the surface charge density on the surface due to the polarization is given as,

But, the polarization $P$ is equal to the $σ_{p}$ then electric field is.

Now the electrical susceptibility $χ$ indicates the degree of polarization $P$ of the dielectric medium to an applied electric field $E$.

Here put the value of $P$ in the equation of electric field then we get,

The dielectric constant $K$ define as the ratio of the electric field without a dielectric $E_{0}$ to the net electric field $E$ with dielectric.

Now we get the relationship between dielectric constant $K$ and susceptibility $χ$.

Now, let’s study the dielectric strength

The dielectric strength defines as the electrical strength of the insulating material.

It means the maximum electrical field such that the dielectric medium retains its insulating property, such electric field is known as the dielectric strength.

Dielectric medium is also defined as the maximum voltage required to produce a dielectric breakdown through the material and it is expressed as,

Revision

This is the relation between the dielectric constant and the electric susceptibility is.

Dielectric medium is also define as the maximum voltage required to produce a dielectric breakdown through the material and it is expressed as,