Q: Solve: 4 \frac{2}{3} + 3 \frac{1}{4}

\frac{(3 \times 4) + 2}{3} + \frac{(3 \times 4) + 1}{4} = \frac{14}{3} + \frac{13}{4} = \frac{(14 \times 4) + (13 \times 3)}{12} = \frac{56 + 39}{12} = \frac{95}{12}

Q: Solve: \frac{4}{3} - \frac{1}{2}

\frac{(4 \times 2) - (1 \times 3)}{6} = \frac{8 - 3}{6} = \frac{5}{6}

Question 1

Satypal walks   \displaystyle \frac{2}{3}    km from a place P towards east and then there    \displaystyle 1\frac{5}{7}    km towards west Where will he be now from P ?

Accepted Answer

Let us denote the distance travelled towards east by positive sign so thus distance of Satypal from the point P would be    \displaystyle \frac{2}{3}    +   \displaystyle (-1\frac{5}{7})      = \displaystyle \frac{2}{3}    +   \displaystyle \frac{-12}{7}      = \displaystyle \frac{2	imes 7}{3	imes 7}    +   \displaystyle \frac{(-12)	imes 3}{7	imes 3}      = \displaystyle \frac{14-36}{21}      = \displaystyle \frac{-22}{ 21 }      = \displaystyle -1\frac{1}{21}    Since it is negative it means Satypal is at a distance    \displaystyle1 \frac{1}{21}    km towards west of P

Question 2

Solve: 4 \frac{2}{3} + 3 \frac{1}{4}

Accepted Answer

\frac{(3 	imes 4) + 2}{3} + \frac{(3 	imes 4) + 1}{4} = \frac{14}{3} + \frac{13}{4} = \frac{(14 	imes 4) + (13 	imes 3)}{12} = \frac{56 + 39}{12} = \frac{95}{12}

Question 3

Divide the sum of  (65/12)  and  (8/3)  by their difference.

Accepted Answer

First we have to find the sum  (65/12)+(8/3) LCM  of  12  and  3  is  12 Then, (65	imes 1)/(12	imes 1)=(65/12) and  (8	imes 4)/(3	imes 4)=(32/12) Now, =(65+32)/12 =(97/12) Now find the difference of  (65/12)-(8/3) LCM  of  12  and  3  is  12 Then, (65	imes 1)/(12	imes 1)=(65/12) (8	imes 4)/(3	imes 4)=(32/12) Now, =(65-32)/12 =(33/12) Now divide  (97/12)\div (33/12) =(97	imes 12)	imes (12/33) =(97	imes 12)/(12	imes 33) =(97	imes 1)/(1	imes 33) =(97/33)

Question 4

Simplify: (2/3)+(5/6)-(1/9)

Accepted Answer

LCM of  3,6,9=18 Now let us change each of the given fraction into an equivalent fraction having  18  as the denominator. (2/3)x(6/6)=(12/18) and  (5/6)x(3/3)=(15/18) and  (1/9)x(2/2)=(2/18) Now, =(12/18)+(15/18)-(2/18) =(12+15-2)/18 =(27-2)/18 =(25/18) =[1(7/18)]

Question 5

Find the sum(8/9)+(7/12)

Accepted Answer

For addition of two unlike fractions,first change them to the like fractions.LCM of 9,12=36Now,let us change each of the given fraction into an equivalent fraction having 36 as the denominator. \dfrac{8}{9}	imes \dfrac{4}{4}=\dfrac{32}{36} \dfrac{7}{12}	imes \dfrac{3}{3}=\dfrac{21}{36} Now.add the like fractions, =\dfrac{32}{36} +\dfrac{21}{36} =\dfrac{32+21}{36} =\dfrac{53}{36} =[1\dfrac{17}{36}]

Question 6

Simplify:  [8(5/6)]-[3(3/8)]+[1(7/12)]

Accepted Answer

First we convert each mixed fraction into an improper fraction. \Rightarrow [8(5/6)]=(53/6) also  \Rightarrow [3(3/8)]=(27/8) and  \Rightarrow [1(7/12)]=(19/12) Then, (53/6)-(27-8)-(19/12) LCM of  6,8,12=24 Now, let us change each of the given fraction into an equivalent fraction having  24   as the denominator. =[(53/6)	imes(4/4)]=(212/24) also  =[(27/8)	imes (3/3)]=(81/24) and  =[(19/12)	imes(2/2)]=(38/24) Now, =(212/24)-(81/24)-(38/24) =[(212-81+38)/24] =[(250-81/24)] =(169/24) =[7(1/24)]

Question 7

4+\dfrac{1}{2}+3\dfrac{1}{2}+9\dfrac{6}{7} .

Accepted Answer

Toppr Ask Answer

Question 8

Solve: \frac{4}{3} - \frac{1}{2}

Accepted Answer

\frac{(4 	imes 2) - (1 	imes 3)}{6} = \frac{8 - 3}{6} = \frac{5}{6}

Question 9

Find the sum 3\dfrac{4}{5}+2\dfrac{3}{10}+1\dfrac{1}{15}

Accepted Answer

First, convert each mixed fraction into an improper fraction.We get, 3\dfrac{4}{5}=\dfrac{18}{5} 2\dfrac{3}{10}=\dfrac{23}{10} 1\dfrac{1}{15}=\dfrac{16}{15} Then, to find out \dfrac{19}{5}+\dfrac{23}{10}+\dfrac{16}{15} , we need to calculate the LCM of the denominators.LCM of  5,10\, \, and \, \, 15=30 Now,let us change each of the given fraction into an equivalent fraction having 30 as the denominator \dfrac{19}{5}	imes\dfrac{6}{6}=\dfrac{114}{30} \dfrac{23}{10}	imes\dfrac{3}{3}=\dfrac{69}{30} \dfrac{16}{15}	imes\dfrac{2}{2}=\dfrac{32}{30} Now, \dfrac{114}{30}+\dfrac{69}{30}+\dfrac{32}{30}= \dfrac{(114+69+32)}{30} =\dfrac{215}{30} =\dfrac{43}{6} =7\dfrac{1}{6}

Question 10

Sarita bought  \dfrac{2}{5}  meter of ribbon and Lalita  \dfrac{3}{4}  meter of ribbon. What is the total length of the ribbon they bought?

Accepted Answer

Length of ribbon Sarita bought  = \dfrac25  meter

Length of
ribbon Lalita bought  = \dfrac34  meter

Total length of
ribbon  = \dfrac25 + \dfrac34

LCM of  5  &  4  is  20

\dfrac {4	imes 2}{5 	imes 4} + \dfrac {3	imes 5}{4	imes 5}

= \dfrac {8}{20} + \dfrac {15}{20}

= \dfrac {23} {20}

Thus,they
bought  \dfrac {23}{20}  meters of ribbon together.

Addition and Subtraction of unlike fractions

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Important Questions

Satypal walks $\frac{2}{3}$ km from a place P towards east and then there $1 \frac{5}{7}$ km towards west Where will he be now from P ?

Solve:
$4 \frac{2}{3} + 3 \frac{1}{4}$

Divide the sum of $(65 / 12)$ and $(8 / 3)$ by their difference.

Simplify: (2/3)+(5/6)-(1/9)

Find the sum
(8/9)+(7/12)

Simplify: $[8 (5 / 6)] - [3 (3 / 8)] + [1 (7 / 12)]$

$4 + \frac{1}{2} + 3 \frac{1}{2} + 9 \frac{6}{7}$ .

Solve:
$\frac{4}{3} - \frac{1}{2}$

Find the sum
$3 \frac{4}{5} + 2 \frac{3}{1 0} + 1 \frac{1}{1 5}$

Sarita bought $\frac{2}{5}$ meter of ribbon and Lalita $\frac{3}{4}$ meter of ribbon. What is the total length of the ribbon they bought?

Addition and Subtraction of unlike fractions

Language

Rate

NEXT VIDEOS

REVISE WITH CONCEPTS

Adding and Subtracting Unlike Fractions

QUICK SUMMARY WITH STORIES

Adding and subtracting fractions

Adding and Subtracting Unlike Fractions

Important Questions

Satypal walks 32​km from a place P towards east and then there 175​km towards west Where will he be now from P ?

Solve: 432​+341​

Divide the sum of (65/12) and (8/3) by their difference.

Simplify: (2/3)+(5/6)-(1/9)

Find the sum (8/9)+(7/12)

Simplify: [8(5/6)]−[3(3/8)]+[1(7/12)]

4+21​+321​+976​.

Solve: 34​−21​

Find the sum 354​+2103​+1151​

Sarita bought 52​ meter of ribbon and Lalita 43​ meter of ribbon. What is the total length of the ribbon they bought?

Satypal walks $\frac{2}{3}$ km from a place P towards east and then there $1 \frac{5}{7}$ km towards west Where will he be now from P ?

Solve:
$4 \frac{2}{3} + 3 \frac{1}{4}$

Divide the sum of $(65 / 12)$ and $(8 / 3)$ by their difference.

Find the sum
(8/9)+(7/12)

Simplify: $[8 (5 / 6)] - [3 (3 / 8)] + [1 (7 / 12)]$

$4 + \frac{1}{2} + 3 \frac{1}{2} + 9 \frac{6}{7}$ .

Solve:
$\frac{4}{3} - \frac{1}{2}$

Find the sum
$3 \frac{4}{5} + 2 \frac{3}{1 0} + 1 \frac{1}{1 5}$

Sarita bought $\frac{2}{5}$ meter of ribbon and Lalita $\frac{3}{4}$ meter of ribbon. What is the total length of the ribbon they bought?