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Gravitational Potential Energy
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Gravitational potential due to uniform r...
Gravitational potential due to uniform ring
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Important Questions
Two bodies of masses
$m$
and
$4m$
are placed at a distance
$r.$
The gravitational potential at a point on the line joining them where the gravitational field is zero is :
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At what height from the surface of earth the gravitation potential and the value of
$g$
are
$−5.4×10_{7}Jkg_{−2}$
and
$6.0ms_{−2}$
respectively? Take the radius of earth as
$6400km$
.
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A particle of mass
$M$
is situated at the centre of spherical shell of same mass and radius
$a$
. The magnitude of the gravitational potential at a point situated at
$a/2$
distance from the centre, will be
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>
Energy required to move a body of mass m from an orbit of radius 2R to 3R is:
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A body of mass 'm' is taken from the earth's surface to the height equal to twice the radius (R) of the earth.
The change in potential energy of body will be -
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A particle is projected vertically upward from the surface of earth (radius
$R_{e}$
) with a kinetic energy equal to half of the minimum value needed for it to escape.The height to which it rises above the surface of earth is
Hard
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>
A black hole is an object whose gravitational field is so strong that even light cannot escape from it. To what approximate radius would earth
$(mass=5.98×10_{24}kg)$
have to be compressed to be a black hole?
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Infinite number of bodies, each of mass
$2kg$
, are situated on
$x−axis$
at distance
$1m,2m,4m,8m,.......$
respectively, from the origin. The resulting gravitational potential due to this system at the origin will be
Hard
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>
The change in potential energy when body of mass m is raised to height
$nR$
from earth's surface is (
$R$
=radius of the earth)
Medium
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>
Define gravitational potential energy. Derive expression for gravitational potential in the gravitational field of earth at distance
$r$
from the centre of the earth.
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>