Solve
Study
Textbooks
Guides
Use app
Login
>>
Class 11
>>
Physics
>>
Gravitation
>>
Gravitational Potential Energy
>>
Gravitational potential energy due to co...
Gravitational potential energy due to continuous mass system
8 Mins
Physics
Language
Rate
NEXT VIDEOS
Escape velocity and its magnitude
8 mins
Critical velocity (orbital speed)
8 mins
Problems Based on Escape Velocity
11 mins
Introduction To Satellite
10 mins
Time period of satellite
8 mins
REVISE WITH CONCEPTS
Gravitational Potential Energy
Example
Definitions
Formulaes
>
Gravitational Potential Energy of a System of Continuous Masses
Example
Definitions
Formulaes
>
QUICK SUMMARY WITH STORIES
Introduction to Gravitational Potential
3 mins
Gravitational Potential due to Point Mass
2 mins
Potential Energy of a System of Continuous Masses
2 mins
Important Questions
Two bodies of masses
$m$
and
$4m$
are placed at a distance
$r.$
The gravitational potential at a point on the line joining them where the gravitational field is zero is :
Medium
JEE Mains
View solution
>
A particle of mass
$M$
is situated at the centre of spherical shell of same mass and radius
$a$
. The magnitude of the gravitational potential at a point situated at
$a/2$
distance from the centre, will be
Medium
View solution
>
At what height from the surface of earth the gravitation potential and the value of
$g$
are
$−5.4×10_{7}Jkg_{−2}$
and
$6.0ms_{−2}$
respectively? Take the radius of earth as
$6400km$
.
Medium
View solution
>
Energy required to move a body of mass m from an orbit of radius 2R to 3R is:
Medium
View solution
>
A body of mass 'm' is taken from the earth's surface to the height equal to twice the radius (R) of the earth.
The change in potential energy of body will be -
Medium
View solution
>
Define gravitational potential energy. Derive expression for gravitational potential in the gravitational field of earth at distance
$r$
from the centre of the earth.
Medium
View solution
>
Infinite number of bodies, each of mass
$2kg$
, are situated on
$x−axis$
at distance
$1m,2m,4m,8m,.......$
respectively, from the origin. The resulting gravitational potential due to this system at the origin will be
Hard
View solution
>
From a solid sphere of mass
$M$
and radius
$R$
a spherical portion of radius
$2R $
is removed, as shown in the figure. Taking gravitational potential
$V=0$
at
$r=∞$
, the potential at the centre of the cavity thus formed is :
$(G=$
gravitational constant).
Medium
View solution
>
If
$g$
is the acceleration due to gravity on the earth's surface, the gain in the potential energy of an object of mass
$m$
raised from the surface of the earth to a height equal to the radius
$R$
of the earth is
Medium
View solution
>
The gravitational potential energy of a body at a distance
$r$
from the centre of earth is
$U$
. Its weight at a distance
$2r$
from the centre of earth is
Medium
View solution
>