Solve
Study
Textbooks
Guides
Use app
Login
>>
Class 11
>>
Physics
>>
Motion in a Straight Line
>>
Acceleration
>>
Velocity - Time Graph - II
Velocity - Time Graph - II
12 Mins
Physics
Language
Rate
NEXT VIDEOS
Velocity - Time Relation in Uniform Acceleration Motion
6 mins
Position - Time Relation in Uniform Acceleration Motion
7 mins
Position-Velocity relation in uniform accelerated Motion
7 mins
Derivation of Equations of Motion (Calculus Method)
8 mins
Displacement of Particle in nth Second
5 mins
REVISE WITH CONCEPTS
Velocity - Time Graph
Example
Definitions
Formulaes
>
Advanced Knowledge of Velocity - Time Graph
Example
Definitions
Formulaes
>
Velocity - Time Graph-Basic
Example
Definitions
Formulaes
>
Velocity-time graph for uniform velocity and uniform acceleration
Example
Definitions
Formulaes
>
View more
QUICK SUMMARY WITH STORIES
Basics of Velocity-Time Graph
3 mins
Displacement From Velocity-Time Graph
2 mins
Velocity-Time Graph
3 mins
Velocity-Time Graph
3 mins
Acceleration From Velocity-Time Graph
3 mins
Problem on Velocity-Time Graph
3 mins
Speed-Time Graph
3 mins
Simple Problem on Speed-Time Graph
2 mins
View more
Important Questions
A particle moves along a straight line such that its displacement at any time
$t$
is given by
$s=t_{3}−6t_{2}+3t+4$
metres. The velocity when the acceleration is zero is:-
Medium
View solution
>
The position x of a particle with respect to time t along x-axis is given by
$x=9t_{2}−t_{3}$
where x is in metres and t is in seconds. What will be the position of this particle when it achieves maximum speed along the + x direction?
Medium
View solution
>
The relation between time t and distance x is
$t=ax_{2}+bx$
where a and b are constants.The acceleration is
Easy
View solution
>
The position
$x$
of a particle varies with time as
$x=at_{2}−bt_{3}$
. The acceleration of particle is zero at time
$T$
equal to
Medium
View solution
>
The acceleration of a particle is increasing linearly with time
$t$
as
$bt$
. The particle starts from the origin with an initial velocity
$v_{0}$
. The distance travelled by the particle in time
$t$
will be
Medium
View solution
>
The position of a particle is given by
$r=3.0ti^−2.0t_{2}j^ +4.0k^m$
where t is in seconds and the coefficients have the proper units for
$r$
to be in metres(a) Find the
$v$
and
$a$
of the particle?
(b) What is the magnitude and direction of velocity of the particle at t = 2.0 s ?
Medium
View solution
>
A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is
Medium
View solution
>
The elevator shown in figure is descending, with an acceleration of 2
$m/s_{2}$
. The mass of the block A is 0.5 kg. The force exerted by the block A on the block B is -
Medium
View solution
>
A particle moving, eastwards with a velocity of
$5m/s$
. In
$10s$
, its velocity changes to
$5m/s$
northwards. The average acceleration in this time is
Medium
View solution
>
The initial velocity of a particle is
$u$
$(att=0)$
and the acceleration is given by
$f=at$
. Which of the following relations is valid?
Medium
View solution
>