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A block of mass 2 kg initially at rest moves under the action of an applied horizontal force of 6 N on a rough horizontal surface. The coefficient of friction between block and surface is 0.1. The work done by the applied force in 10 s is (Take g=10 ms−2).
- 200 J
- 600 J
- −200 J
- −600 J
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Solution
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The various forces acting on the block is as shown in the figure.
Here, m=2 kg,μ=0.1,F=6 N,g=10 ms−2
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A force F=10√2N acts an angle of 45o above the horizontal on a 2kg block placed on a rough horizontal surface. The coefficient of friction between the block and surface is 0.2 Find the work done by the force F on the block in 5s initially the block is at rest. [Take g=10/s2]
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Q4
A block of unknown mass is at rest on a rough horizontal surface. A force F is applied to the block. The graph in the figure shows the acceleration of the block w.r.t the applied force.
The mass of the block and coefficient of friction are (g=10 m/s2)
The mass of the block and coefficient of friction are (g=10 m/s2) View Solution