A simple harmonic motion has an amplitude A and time period T. The time required by it to travel x=A to x=A2 is:
T/6
T/3
T/4
T/2
A
T/4
B
T/3
C
T/2
D
T/6
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Solution
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x=Acosωt
t=0,x=A
At x=A2,
A2=Acosωt
ωt=π3
2πTt=π3
t=T6 where T is time period
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