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Standard XII
Mathematics
Question
Evaluate:
∫
√
15
√
8
x
√
1
+
x
2
.
d
x
15
8
37
3
37
6
37
9
A
37
3
B
15
8
C
37
6
D
37
9
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Solution
Verified by Toppr
∫
√
15
√
8
x
√
1
+
x
2
d
x
Let
z
=
1
+
x
2
⟹
d
z
=
2
x
d
x
⟹
x
d
x
=
d
z
2
For,
x
=
√
8
,
z
=
9
and for
x
=
√
15
,
z
=
16
Hence, integration becomes-
∫
16
9
√
z
d
z
2
=
1
2
⎡
⎢ ⎢ ⎢
⎣
z
(
1
2
+
1
)
1
2
+
1
⎤
⎥ ⎥ ⎥
⎦
16
9
=
1
2
×
2
3
[
z
(
3
2
)
]
16
9
=
1
3
[
16
(
3
2
)
−
9
(
3
2
)
]
=
1
3
[
64
−
27
]
=
37
3
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Similar Questions
Q1
Evaluate:
∫
√
15
√
8
x
√
1
+
x
2
.
d
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View Solution
Q2
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Q3
The distance of the point
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−
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,
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,
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)
from the line
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=
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Q4
Observe the given multiplies of 37
37
×
3
=
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×
6
=
222
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×
9
=
333
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×
12
=
444
.
.
.
Find the product of
37
×
27
?
View Solution
Q5
Observe the given multiples of 37.
37
×
3
=
111
37
×
6
=
222
37
×
9
=
333
37
×
12
=
444
-------------------------------
Find the product of
37
×
27
View Solution