Find the value of p of the following equation-123-45-9-p-45-p times 9-0

Question

Toppr Admin · Accepted Answer

123-x2212-45-x2212-9-x2212-p-45-x2212-p-xD7-9-0-x21D2-123-x2212-36-x2212-p-45-x2212-9p-0-x21D2-123-x2212-36-x2212-p-45-x2212-9p-0-x21D2-x2212-10p-132-0-x21D2-x2212-10p-x2212-132-x2234-p-x2212-132-x2212-10-665

Find the value of $p$ of the following equation.
$123 - (45 - 9) - p + 45 - p \times 9 = 0$

$123 - (45 - 9) - p + 45 - p \times 9 = 0$
$\Rightarrow 123 - (36) - p + 45 - 9 p = 0$
$\Rightarrow 123 - 36 - p + 45 - 9 p = 0$
$\Rightarrow - 10 p + 132 = 0$
$\Rightarrow - 10 p = - 132$
$∴ p = \frac{- 132}{- 10} = \frac{66}{5}$

Find the value of p of the following equation.123−(45−9)−p+45−p×9=0

123−(45−9)−p+45−p×9=0⇒123−(36)−p+45−9p=0⇒123−36−p+45−9p=0⇒−10p+132=0⇒−10p=−132∴p=−132−10=665

Find the value of $p$ of the following equation.
$123 - (45 - 9) - p + 45 - p \times 9 = 0$

$123 - (45 - 9) - p + 45 - p \times 9 = 0$
$\Rightarrow 123 - (36) - p + 45 - 9 p = 0$
$\Rightarrow 123 - 36 - p + 45 - 9 p = 0$
$\Rightarrow - 10 p + 132 = 0$
$\Rightarrow - 10 p = - 132$
$∴ p = \frac{- 132}{- 10} = \frac{66}{5}$