In an isolated parallel plate capacitor of capacitance C the four surfaces have charges Q1,Q2,Q3 and Q4 as shown in the figure. The potential difference between the plates is :
Q1+Q2C
|Q2C|
|Q3C|
1C[(Q1+Q2)−(Q3−Q4)]
A
|Q2C|
B
|Q3C|
C
Q1+Q2C
D
1C[(Q1+Q2)−(Q3−Q4)]
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Solution
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For parallel plate
capacitor, Q2 andQ3 must be same and equal in
magnitude.i.e,|Q2|=|Q3|
So, potential
difference between the plates, V=|Q2|C=|Q3|C
Ans: (B),(C)
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