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Question

Mole fraction of solvent in an aqueous solution is 0.8. What is the molality of this solution in mol/kg?

A
$$13.88$$
B
$$55.55$$
C
$$27.77$$
D
$$6.94$$
Solution
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Correct option is B. $$13.88$$
$$X_{solvent} = 0.8$$
$$X_{solute} = 0.2$$
$$m = \dfrac{X_{solute}}{X_{solvent}} \times \dfrac{1000}{18} = \dfrac{0.2}{0.8} \times \dfrac{1000}{18} = \dfrac{250}{18} = 13.88 mol/kg$$

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