Mole fraction of solvent in an aqueous solution is 0-8- What is the molality of this solution in mol-kg-

Question

Toppr Admin · Accepted Answer

Correct option is B- -13-88-X-solvent- - 0-8-X-solute- - 0-2-m - -dfrac-X-solute-X-solvent- -times -dfrac-1000-18- - -dfrac-0-2-0-8- -times -dfrac-1000-18- - -dfrac-250-18- - 13-88 mol-kg-

Mole fraction of solvent in an aqueous solution is 0.8. What is the molality of this solution in mol/kg?

Correct option is B. $$13.88$$
$$X_{solvent} = 0.8$$
$$X_{solute} = 0.2$$
$$m = \dfrac{X_{solute}}{X_{solvent}} \times \dfrac{1000}{18} = \dfrac{0.2}{0.8} \times \dfrac{1000}{18} = \dfrac{250}{18} = 13.88 mol/kg$$

Mole fraction of solvent in an aqueous solution is 0.8. What is the molality of this solution in mol/kg?

Correct option is B. $$13.88$$$$X_{solvent} = 0.8$$$$X_{solute} = 0.2$$$$m = \dfrac{X_{solute}}{X_{solvent}} \times \dfrac{1000}{18} = \dfrac{0.2}{0.8} \times \dfrac{1000}{18} = \dfrac{250}{18} = 13.88 mol/kg$$

Correct option is B. $$13.88$$
$$X_{solvent} = 0.8$$
$$X_{solute} = 0.2$$
$$m = \dfrac{X_{solute}}{X_{solvent}} \times \dfrac{1000}{18} = \dfrac{0.2}{0.8} \times \dfrac{1000}{18} = \dfrac{250}{18} = 13.88 mol/kg$$