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Standard XII
Physics
Dimensional Analysis
Question
The dimensional formula of electric flux is:
[
M
1
L
−
3
T
3
A
1
]
[
M
1
L
1
T
−
2
]
[
M
1
L
3
T
−
3
A
−
1
]
[
M
2
L
2
T
−
2
A
−
2
]
A
[
M
1
L
1
T
−
2
]
B
[
M
1
L
−
3
T
3
A
1
]
C
[
M
1
L
3
T
−
3
A
−
1
]
D
[
M
2
L
2
T
−
2
A
−
2
]
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Solution
Verified by Toppr
Electric flux
ϕ
=
∫
→
E
.
→
s
The dimension of
ϕ
=
dimension fo
E
×
dimension of
s
[
ϕ
]
=
[
M
1
L
1
T
−
2
]
[
A
T
]
−
1
[
L
2
]
=
[
M
1
L
3
T
−
3
A
−
1
]
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[
M
1
L
2
T
−
3
A
−
2
]
is the dimensional formula of :
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Q2
Dimensional formula of the product of the physical quantity P and Q is
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L
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and the dimensional formula of
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Q3
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Q4
Match List I with II and select the correct answer:
List-I
List-II
A.Spring constant
1.
M
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L
2
T
−
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2.
M
0
L
0
T
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Q5
Match List I with List II and select the correct
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List - I
List - II
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M
1
L
2
T
−
2
]
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M
0
L
0
T
−
1
]
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M
1
L
0
T
−
2
]
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M
1
L
−
1
T
−
2
]
View Solution