0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The molar conductivity of 0.04 M solution of MgCl2 is 10-2 S cm-1. at 298 K in a cell with electrodes that are 2cmin in surface area and 0.5 cm apart. Calculate how much current (in amp.) will flow when potential different between the electrodes is 25 Volt.

Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1
The molar conductivity of 0.04 M solution of MgCl2​ is 200 S cm3 mol1 at 298 K. A cell with electrodes that are 2.0 cm2 in surface area and 0.50 cm apart is filled with MgCl2​ solution. How much current will flow when the potential difference between the two electrodes is 5.0 V?
View Solution
Q2
The equivalent conductance of 0.1 N solution of MgCl2 is 25 Ω1cm2eq1 at 25 C. A cell with electrodes that are 2 cm2 in surface area and 0.5 cm apart is filled with 0.1 N MgCl2 solution. How much current (in A) will flow when the potential difference between the electrodes is 5 Volts?
View Solution
Q3
The eqivalent conductance of 0.10 N solution of MgCl2 is 97.1mhocm2eq1. A cell with electrodes that are 1.50cm2 in surface area and 0.50 cm apart is filled with 0.1N MgCl2 solution. The current (in amp) that will flow when the potential difference between the electrodes is 5 volts is 145×10x, then what is the value of x?
View Solution
Q4
The molar conductance of 0.05 M solution of MgCl2 is 194.5Ω1cm2mol1 at 25C, A cell with electrods having 1.50cm2 surface area and 0.50 cm apart is filled with 0.05 M solution mgCl2. How much current will flow when the potential difference between the electrodes is 5.0 V ?
View Solution
Q5
The molar conductivity of 0.04 M solution of MgCl2 is 200Scm2mol1 at 298 K. A cell with electrodes that are 2.0 cm2 in surface area and 0.50 cm apart is filled with MgCl2 solution.
Conductance of MgCl2 solution is:
[1 Mark]

View Solution