The photo-electric threshold wavelength for a metal is 6620 Ao. Its work function is (given h=6.62×10−34Js,c=3×108 m/s)
1.87 eV
2.00 eV
3.00 eV
2.87 eV
A
1.87 eV
B
3.00 eV
C
2.87 eV
D
2.00 eV
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Solution
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ϕ=hcλT
=1240662(hc=1240eV−nm)
=1.87eV So, the answer is option (A).
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