Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Standard XII
Physics
Question

A car accelerates from rest at constant rate α for some time after which it deaccelerates at a constant rateβ to come to rest. The max. velocity v reached if total time is t second is :
  1. v=t(αβα+β)
  2. v=t(αβα−β)
  3. v=t(α2α+β)
  4. v=t(β2α−β)

A
v=t(αβα+β)
B
v=t(αβα−β)
C
v=t(α2α+β)
D
v=t(β2α−β)
Open in App
Solution
Verified by Toppr

Was this answer helpful?
0
Similar Questions
Q1
A car accelerates from rest at constant rate α for some time after which it deaccelerates at a constant rateβ to come to rest. The max. velocity v reached if total time is t second is :
View Solution
Q2
If α and β are the roots of the equation 2x2−3x−1=0, find the values of.
(i) α2+β2
(ii) αβ+βα
(iii) α−β if α>β(iv) (α2β+β2α)
(v) (α+1β)(1α+β)
(vi) α4+β4
(vii) α3β+β3α
View Solution
Q3
A car accelerates from rest at a constant rate of α for some time, after which it decelerates at a constant rate of β to come to rest. If the total time elapsed is t second, then calculate
a. the maximum velocity attained by the car, and
b.the total displacement travelled by car in terms of α,β and t.
View Solution
Q4
The elevation of a tower due North of a station A is α or (at a place due South of it is α) and at another station B due West of A it is β. Prove that the height of the tower is

AB√(cot2β−cot2α)

or ABtanαtanβ√(tan2α−tan2β)

or ABsinαsinβ√(sin2α−sin2β)

or ABsinαsinβ[sin(α+β)sin(α−β)]1/2 if sin2α−sin2β=sin(α+β)sin(α−β)


View Solution
Q5
A train starts from rest and its speed increases at a constant rate α to v and then remains constant for an interval and finally decreases to zero at a constant rate β. The total distance travelled by train is l. The time taken to complete the journey is t. Then,
View Solution