$1)$ The transverse displacement of a string (clamped at its both ends) is given by

$y (x . t) = 0.06 sin (\frac{2 π}{3} x) cos (120 π t)$ where $x$ and $y$ are in $m$ and $t$ in $s$ . The length of the string is $1.5 m$ and its mass is $3.0 \times 10^{- 2} k g$ . Answer the following:
$a)$ Does the function represent a travelling wave or a stationary wave?

$2)$ The transverse displacement of a string (clamped at its both ends) is given by $y (x . t) = 0.06 sin (\frac{2 π}{3} x) cos (120 π t)$ where $x$ and $y$ are in $m$ and $t$ in $s$ . The length of the string is $1.5 m$ and its mass is $3.0 \times 10^{- 2} k g$ . Answer the following:
$b)$ Interpret the wave as a superposition of two waves travelling in opposite directions. What is the wavelength, frequency, and speed of each wave?

$3)$ .The transverse displacement of a string (clamped at its both ends) is given by
$y (x . t) = 0.06 sin (\frac{2 π}{3} x) cos (120 π t)$ where $x$ and $y$ are in $m$ and $t$ in $s$ . The length of the string is $1.5 m$ and its mass is $3.0 \times 10^{- 2} k g$ . Answer the following:
$C)$ Determine the tension in the string?

A string is clamped at both the ends and it is vibrating in its 4th harmonic. The equation of the stationary wave is Y=0.3 sin(0.157x) cos(200ml). The length of the string is : (All quantities are in SI units.) Options : 80 m 60 m 340 m