Solve
Guides
Join / Login
Use app
Login
0
You visited us
0
times! Enjoying our articles?
Unlock Full Access!
Standard IX
Mathematics
Question
Find
x
+
u
+
y
+
z
50
Open in App
Solution
Verified by Toppr
x
=
z
u
=
y
.
.
.
.
.
.
.
.
.
.
.
.
.
.
(
1
)
(Vertically opposite Angles)
Now, EF is a straight line
So,
35
o
+
y
+
20
o
+
z
=
180
o
⇒
y
+
z
=
180
o
−
55
o
⇒
y
+
z
=
125
o
Hence,
x
+
u
+
y
+
z
50
=
z
+
y
+
y
+
z
50
=
2
(
y
+
z
)
50
=
2
∗
125
o
50
=
5
o
Was this answer helpful?
0
Similar Questions
Q1
Find
x
+
u
+
y
+
z
50
View Solution
Q2
If
u
=
y
z
+
z
x
Show that
x
∂
u
∂
x
+
y
∂
u
∂
y
+
z
∂
u
∂
z
=
0
View Solution
Q3
Solve the following equations :
x
+
y
+
z
+
u
=
2
a
,
x
+
y
−
z
−
u
=
2
b
,
x
−
y
+
z
−
u
=
2
c
,
x
−
y
−
z
+
u
=
2
d
.
View Solution
Q4
If
u
=
(
x
3
+
y
3
+
z
3
)
(
x
+
y
+
z
)
then
x
∂
u
∂
x
+
y
∂
u
∂
y
+
z
∂
u
∂
z
=
?
View Solution
Q5
If
u
=
∣
∣ ∣ ∣
∣
1
1
1
x
y
z
x
2
y
2
z
2
∣
∣ ∣ ∣
∣
then
x
∂
u
∂
x
+
y
∂
u
∂
y
+
z
∂
u
∂
z
=
View Solution