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Give the mechanism involved in the esterification of a carboxylic acid with alcohol.
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(i) Carboxylic acid reacts with alcohols in presence of mineral acid as catalyst and forms esters. This reaction is called estirification
CH3COOHAceticacid+C2H5OHEthanolH+−−→CH3COOC2H5Ethylacetate+H2O
(ii) Mechanism of esterification: Protonation of the −OH group of the acid, enhances the nucleophilic attack by alcohol to give the ester
Step 1: Protonation of carboxylic acid.
Step 2: Attack by nucleophile
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