If ax=by=cz & y2=xz, then the value of logba will be
logcb
logbc
alogcb
None of these
A
logcb
B
logbc
C
alogcb
D
None of these
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Solution
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Letax=by=cz=PlogaP=xlogbP=ylogcP=zy2=xzSologbP⋅logbP=logaPlogcPAssuming base P, we getlogPlogb×logPlogb=logPlogalogPlogcSo we can write1logb1logb=1loga1logclogalogb=logblogc
logba=logcb
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