In the circuit shown in Fig, the current I has a value equal to
1A
2A
4A
3.5A
A
1A
B
4A
C
3.5A
D
2A
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Solution
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The equivalent resistances of each combinations,
For 15 ohm resistances in parallel
Req1=153=5Ω
For 4 ohm resistances in parallel
Req2=42=2Ω
Hence the current through circuit is
I=EReq1+Req2+2+r
I=105+2+2+1=1 A
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