- left- Fe- F - 6 - right- - 4- - is paramagnetic because-F- us a chelating ligand-F- is a stronger ligand-F- is a flexidinate ligand-F- is a weaker ligand

Question

Toppr Admin · Accepted Answer

-FeF6-4-x2212-xA0- is paramagnetic because F-x2212-xA0- is a weaker ligand- Due to this- spin free or high spin complex is formed which contains four unpaired electrons- Fe2- has 3d6 electronic configuration-

${[F e F_{6}]}^{4 -}$ is paramagnetic because:
$F^{-}$ us a chelating ligand
$F^{-}$ is a stronger ligand
$F^{-}$ is a flexidinate ligand
$F^{-}$ is a weaker ligand

${[F e F_{6}]}^{4 -}$ is paramagnetic because $F^{-}$ is a weaker ligand. Due to this, spin free or high spin complex is formed which contains four unpaired electrons. $F e^{2 +}$ has $3 d^{6}$ electronic configuration.

[FeF6]4− is paramagnetic because:F− us a chelating ligandF− is a stronger ligandF− is a flexidinate ligandF− is a weaker ligand

[FeF6]4− is paramagnetic because F− is a weaker ligand. Due to this, spin free or high spin complex is formed which contains four unpaired electrons. Fe2+ has 3d6 electronic configuration.

${[F e F_{6}]}^{4 -}$ is paramagnetic because:
$F^{-}$ us a chelating ligand
$F^{-}$ is a stronger ligand
$F^{-}$ is a flexidinate ligand
$F^{-}$ is a weaker ligand

${[F e F_{6}]}^{4 -}$ is paramagnetic because $F^{-}$ is a weaker ligand. Due to this, spin free or high spin complex is formed which contains four unpaired electrons. $F e^{2 +}$ has $3 d^{6}$ electronic configuration.