The potential energy of a satellite of mass m revolving at height R above the surface of the earth where R= radius of earth is
−mgR
−mgR2
−mgR4
−mgR3
A
−mgR
B
−mgR2
C
−mgR4
D
−mgR3
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Solution
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PE=−GMm2R−(−GMmR)=−GMm2R
Also,
g=GMR2
Putting the value of GMR in equation (1) we get,
PE=−gmR2
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