The work done in taking a unit positive charge from P to A is WA and from P to B is WB. Then :
WA>WB
WA=WB
WA<WB
WA+WB
A
WA+WB
B
WA<WB
C
WA>WB
D
WA=WB
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Solution
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As potential at A and B is the same VA=VB=kQ/d. and W=qΔV ΔV in both the cases is same. So work done in both the cause will be the same.
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