Two charges −5μC and +10μC are placed 20 cm apart. The net electric field at the mid-point between the two charge is
4.5×105N/C directed towards +10μC
13.5×105N/C directed towards −5μC
13.5×105N/C directed towards +10μC
4.5×105N/C directed towards −5μC
A
4.5×105N/C directed towards +10μC
B
13.5×105N/C directed towards +10μC
C
4.5×105N/C directed towards −5μC
D
13.5×105N/C directed towards −5μC
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Solution
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R.E.F image
¯Enet=¯E1+¯E2
=K(5×10−6)10×10−2+K(10×10−6)10×10−2
⇒9×109[5×10−5+10×10−5]
⇒135×104 N\C
¯Enet13.5×105 N/C towards −5μc
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