Take two equalities simultaneously we get
2x−13=y+65 and y+65=3x−y7
⟹ 10x−5=3y+18 and 7y+42=15x−5y
⟹ 10x−3y=23 .......... (1) and 15x−12y=42 .......... (2)
from eq(2) we can get the value of x in terms of y i.e, x=42+12y15
now simply substitute this x value in eq(1) from where we can calculate the value of y and then substitute the y in any eq we can find the value of x , so
Solving (1) and (2) simultaneously we get
x=2
Substituting x in (1) we get y=−1.
Hence, x=2;y=−1.