A circular conductor is made of a uniform wire of resistance 2 x 10−3 ohm/metre and the diameter of this circular conductor is 2 metres. Then the resistance measured between the ends of the diameter is (in ohms)
π×10−3
2π×10−3
4π×10−3
4×10−3
A
π×10−3
B
4×10−3
C
4π×10−3
D
2π×10−3
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Solution
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The resistance per unit length is given to be R′=2×10−3 The length can be calculated as L=π×D, where D is given diameter of 2 m. Hence L=2π
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