A convex lens of focal length 30 cm. is made of a material of refractive index 53. When it is placed in a liquid its focal length is increased by 50 cm. The refractive index of the liquid is
54
43
74
65
A
54
B
74
C
65
D
43
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Solution
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f1=30cm;μ1=53;μ2=?;f′=80cm
f1f2=(μ1/μ2−1)(μ1−1)
3080=(53μ−1)23
3080×23=(53μ−1)
54=53μ
⇒μ=43
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