An electron and a proton are accelerated through the same potential difference. The ratio of their de Broglie wavelengths (λeλp ) is
1
memp
mpme
√mpme
A
1
B
mpme
C
√mpme
D
memp
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Solution
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λe=h√2meeV
λp=h√2mpeV
λeλp=√mpme
So, the answer is option (D).
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