An object is placed 50 cm from a lens produces a virtual image a distance of 10 cm in front of the lens- Draw a diagram to show the formation of image and calculate the focal length of the lens-

Question

Toppr Admin · Accepted Answer

Distance of object from the mirror u-x2212-50 cmDistance of image from the mirror v-x2212-10 cmFor lens- we know1f-1v-x2212-1u1f-1-x2212-10-x2212-1-x2212-50f-x2212-12-5cmIt is a concave lens-

An object is placed 50 cm from a lens produces a virtual image at a distance of 10 cm in front of the lens. Draw a diagram to show the formation of image and calculate the focal length of the lens.

Distance of object from the mirror $u = - 50$ cm
Distance of image from the mirror $v = - 10$ cm
For lens, we know
$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$
$\frac{1}{f} = \frac{1}{- 10} - \frac{1}{- 50}$
$f = - 12.5 c m$
It is a concave lens.

An object is placed 50 cm from a lens produces a virtual image at a distance of 10 cm in front of the lens. Draw a diagram to show the formation of image and calculate the focal length of the lens.

Distance of object from the mirror u=−50 cmDistance of image from the mirror v=−10 cmFor lens, we know1f=1v−1u1f=1−10−1−50f=−12.5cmIt is a concave lens.

Distance of object from the mirror $u = - 50$ cm
Distance of image from the mirror $v = - 10$ cm
For lens, we know
$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$
$\frac{1}{f} = \frac{1}{- 10} - \frac{1}{- 50}$
$f = - 12.5 c m$
It is a concave lens.