If the area of a parallelogram is 144 operatorname - cm - - - 2 - and its base is 9 cm- then its height is 16 cm8 cm12 cm24 cm

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Toppr Admin · Accepted Answer

Area of parallelogram - base-xD7- heightGiven - base -9-xA0-cm-xA0-xA0-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-area -144-xA0-cm2-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-Let height be h-x21D2- 144-xA0-cm2-9cm-xD7-h-x21D2- h-144-xA0-cm29-xA0-cm-x2234- h-16-xA0-cm

If the area of a parallelogram is $144 {cm}^{2}$ and its base is $9 c m$ . then its height is
$16 c m$
$8 c m$
$12 c m$
$24 c m$

Area of parallelogram $=$ base $\times$ height

Given : base $= 9 c m,$
area $= 144 c m^{2}$
Let height be $h$

$\Rightarrow$ $144 {c m}^{2} = 9 c m \times h$

$\Rightarrow$ $h$ $= \frac{144 {c m}^{2}}{9 c m}$

$∴$ $h = 16 c m$

If the area of a parallelogram is 144cm2 and its base is 9cm. then its height is 16cm8cm12cm24cm

Area of parallelogram = base× heightGiven : base =9 cm, area =144 cm2 Let height be h⇒ 144 cm2=9cm×h⇒ h=144 cm29 cm∴ h=16 cm

If the area of a parallelogram is $144 {cm}^{2}$ and its base is $9 c m$ . then its height is
$16 c m$
$8 c m$
$12 c m$
$24 c m$

Area of parallelogram $=$ base $\times$ height

Given : base $= 9 c m,$
area $= 144 c m^{2}$
Let height be $h$

$\Rightarrow$ $144 {c m}^{2} = 9 c m \times h$

$\Rightarrow$ $h$ $= \frac{144 {c m}^{2}}{9 c m}$

$∴$ $h = 16 c m$