In given fig., AD=BC and ∠BAD=∠ABC, then ∠ACB equals :
∠BAD
∠BDA
∠BAC
∠ABD
A
∠BDA
B
∠BAC
C
∠ABD
D
∠BAD
Open in App
Solution
Verified by Toppr
In △ADB and △ACB
AB=AB (common side)
AD=BC (given)
∠BAD=∠ABC (given)
∴△ADB≅ACB by SAS congruence rule.
Now corresponding angles of congruent triangles are equal
⇒ACB=∠ADB
Was this answer helpful?
19
Similar Questions
Q1
In given fig., AD=BC and ∠BAD=∠ABC, then ∠ACB equals :
View Solution
Q2
Given :- AC=AD ∠CAB=∠BAD To prove :- △ABC≅△ABD Proof :- 9n△ABC & △ABD AC=AD ∠CAB=∠BAD AB=BA △ABC≅△ABD BC=BD
View Solution
Q3
∆ ABC and ∆ ABD are on a common base AB, and AC = BD and BC = AD as shown in Fig. 18. Which of the following statements is true?
(i) ∆ ABC ≅ ∆ ABD
(ii) ∆ ABC ≅ ∆ ADB
(iii) ∆ ABC ≅ ∆ BAD