The angle of incidence for a ray of light at a refracting surface of a prism is 45o. The angle of prism is 60o. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are
45o;1√2
30o;√2
30o;1√2
45o;√2
A
45o;1√2
B
30o;√2
C
45o;√2
D
30o;1√2
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Solution
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Angle of incidence, i=450
Angle of prism, A=600
Angle of minimum deviation, δm=2i−A=300
⇒μ=sin(A+δm2)sinA2=sin450sin300=2√2=√2
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