The Jupiter's period of revolution around the Sun is 12 times that of the Earth. Assuming the planetary orbits to be circular, find how many times the distance between the Jupiter and the Sun exceeds that between the Earth and the Sun.
10.2 times
5.2 times
3 times
6.4 times
A
10.2 times
B
3 times
C
6.4 times
D
5.2 times
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Solution
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Let, The time of revolution of Jupiter is Tj and the radius of orbit of revolution of Jupiter is rj
The time of revolution of Earth is Te
The radius of orbit of revolution of Earth is re
According to Kepler's Law
T2∝r3
⇒T2j∝r3j and T2e∝r3e
∴r3jr3e=T2jT2e
∴rjre=(TjTe)23
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