You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question
28 \( / \) hin right angled triangle ABC, right angled at \( \mathrm { c } , \mathrm { M } \) is the mid point of
hypotenuse \( \mathrm { AB } \mathrm { C } \) is joined to \( \mathrm { M } \) and produced to a point \( \mathrm { D } \) such that DM-CM.
(iijoBC \( = 90 ^ { \circ } \) . (iii) \( \Delta D B C \cong \Delta A C B \)
Open in App
Solution
Verified by Toppr
Was this answer helpful?
0
Similar Questions
Q1
In right triangle ABC, right angled at C,M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM=CM. Point D is joined to point B (see figure). Show that: (i) ΔAMC≅ΔBMD (ii) ∠DBC is a right angle. (iii) ΔDBC≅ΔACB (iv) CM=12AB
View Solution
Q2
In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). Show that: ΔDBC≅ΔACB
(3 Marks)
View Solution
Q3
In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). Show that: ΔDBC≅ΔACB
View Solution
Q4
Question 8 (iii) In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). Show that: ΔDBC≅ΔACB
View Solution
Q5
In a right △ABC, right angled at C, M is the mid point of the hypotenuse of AB. C is joined to M produced to a point D such that DM=CM. Point D is joined to point B. Then