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(3) For the For the reaction:2H2(g) +O2(g) →2H20 AH = - 571kJ bond energy of (H-H) = 435 kJ; of (0=0) =498KJ; then the average bond energy of O-H bond using the above data 1) 484kJ 2) -84kJ 3) 271kJ 4) - 271kJ

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Q1
For the reaction,
2H2(g)+O2(g)⟶2H2O(g);ΔH=−571kJ
bond energy of (H−H)=435kJ; of (O=O)=498kJ,
then calculate the average bond energy of (O−H) bond using the above data.
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Q2

For the reaction,

2H2(g)+O2(g)→2H2O(g); ΔH=−571 kJ.

Bond energies: (H−H)=435 kJ, (O=O)=498 kJ.

Calculate the average bond energy of (O−H) using the above data.


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Q3
The average O−H bond energy in H2O with the help of following data:
(1) H2O(l)→H2O(g);△H=+40.6 kJ mol−1
(2) 2H(g)→H2(g);△H=−435.0 kJ mol−1
(3) O2(g)→2O(g);△H=+489.6 kJ mol−1
(4) 2H2(g)+O2(g)→2H2O(l);△H=−571.6 kJ mol−1
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Q4
For the reaction, O(g)+O2(g)→O3(g);ΔHo=−107.2 kJ. Hence, the average bond energy in O3 is:
(Assume O=O bond energy 498.8 kJ mol−1)

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Q5
XeF2(g)+H2(g)→2HF(g)+Xe(g), ΔHo=−430 kJ
Bond energy →H−H=435 kJ/mol→H−F=565 kJ/mol
Calculate average bond energy of Xe−F bond.

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