A charged particle of unit mass and unit charge moves with velocity →v=(8^i+6^j)ms−1 in a magnetic field of →B=2^kT. Choose the correct alternative(s).
the path of the particle may be x2+y2−4x−21=0
the time period of the particle will be 3.14s
the path of the particle may be x2+y2=25
the path of the particle may be y2+z2=25
A
the time period of the particle will be 3.14s
B
the path of the particle may be x2+y2=25
C
the path of the particle may be y2+z2=25
D
the path of the particle may be x2+y2−4x−21=0
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Solution
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→v=8^i+6^j →B=2^k m=1 q=1 r=mvqB=1×√82+621×2=5
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