Find the speed of an electron with kinetic energy 1 eV
589.92×105ms−1
50.92×105ms−1
599.92×105ms−1
5.92×105ms−1
A
599.92×105ms−1
B
589.92×105ms−1
C
50.92×105ms−1
D
5.92×105ms−1
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Solution
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K.E.=1eV =1.6×10−19J Mass of electron, m=9.1×10−31㎏ ∴K.E.=12mv2 ⇒v=√2K.E.m=√2×1.6×10−199.1×10−31 =5.92×105m/s
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