A parallel-plate air capacitor has a capacitance of 4μF what be its new capacitance if a slab of dielectric constant 5 is introduced filling the entire space between the two plates?
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Solution
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The capacitance is given as,
C=εAd
4=εAd
The new capacitance is given as,
Cn=5εAd
Cn=5×4
Cn=20μF
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